-16=-16t^2+0t

Solution for -16=-16t^2+0t equation:

-16=-16t^2+0t

We move all terms to the left:

-16-(-16t^2+0t)=0

We get rid of parentheses

16t^2-0t-16=0

We add all the numbers together, and all the variables

16t^2-1t-16=0

a = 16; b = -1; c = -16;
Δ = b2-4ac
Δ = -12-4·16·(-16)
Δ = 1025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1025}=\sqrt{25*41}=\sqrt{25}*\sqrt{41}=5\sqrt{41}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-5\sqrt{41}}{2*16}=\frac{1-5\sqrt{41}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+5\sqrt{41}}{2*16}=\frac{1+5\sqrt{41}}{32}
$